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Home » Queries & Discussions » Protein X has 2 trytophans and 1 tyrosine, its M.W is 20,000da. one molar tryptophan and one molar tyrosine solns give A at 280nm of 5500 & 1490 respt. What A at 280nm will u expect for 0.2mg/ml of protein X soln??

Protein X has 2 trytophans and 1 tyrosine, its M.W is 20,000da. one molar tryptophan and one molar tyrosine solns give A at 280nm of 5500 & 1490 respt. What A at 280nm will u expect for 0.2mg/ml of protein X soln??

Protein X has 2 trytophans and 1 tyrosine, its M.W is 20,000da. one molar tryptophan and one molar tyrosine solns give A at 280nm of 5500 & 1490 respt. What A at 280nm will u expect for 0.2mg/ml of protein X soln??

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2 comments

  1. To calculate the absorbance of a 1M solution of a protein you simply count up the number of Tryptophan residues and multiply that by the absorbance of a one molar solution of Tryptophan. Then add that to the number of Tyrosine residues multiplied by the absorbance of a one molar solution of Tyrosine, and the sum is the absorbance of 1M of the whole molecule. So we use this simple equation;

    Molar Extinction Coefficient = (Number of Tryptophan residues X 5500) + (Number of Tyrosine residues X 1490)

    = 2 x 5500 + 1 x 1490

    = 12490

    absorbance, can be further calculated by simply dividing the Molar Extinction Coefficient by the molecular weight of Protein X which in this case is 20,000

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