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What is the number of hydrogen bonds in a b-DNA of 1000 base pairs with the proportion of C,A,T in one of the strands corresponding to 60% 30% and 10% respectively?

By Maya Singh

Question:

What is the number of hydrogen bonds in a b-DNA of 1000 base pairs with the proportion of C,A,T in one of the strands corresponding to 60% 30% and 10% respectively?

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One comment

  1. Ace The Race Geek

    As we can clearly see from the question given above that C is 60%, A is 30% and T is 10%.
    Total Number of Base Pairs = 1000.
    Now, C = 60% of 1000 = X 1000 = 600.
    A = 30% of 1000 = X 1000 = 300.
    T = 10% of 1000 = X 1000 = 100.
    As per the Watson-Crick structure, three hydrogen bonds can form between G and C, and only two can form between A and T.
    Hence, there are 600 Cs that will pair complementary to G on the other strand with three hydrogen bonds. And 300 As that will pair complementary to T on the other strand with two hydrogen bonds and also 100 Ts that will pair complementary to a on the other strand with two hydrogen bonds.
    Therefore, we have,
    3 X 600 + 2 X 300 + 2 X 100
    = 1800 + 600 + 200
    = 2600.
    We have total of 2600 hydrogen bonds.

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