By Suman Patra

Question:

Frequencies of alleles A and a in a population at hardy weinberg equilibrium are 0.7 and 0.3 respectively. In a random sample of 250 individuals taken from the population how many are expected to be heterozygous?

Friday , 18 January 2019

Breaking News

Home » Queries & Discussions » Frequencies of alleles A and a in a population at hardy weinberg equilibrium are 0.7 and 0.3 respectively. In a random sample of 250 individuals taken from the population how many are expected to be heterozygous?

By Suman Patra

Question:

Frequencies of alleles A and a in a population at hardy weinberg equilibrium are 0.7 and 0.3 respectively. In a random sample of 250 individuals taken from the population how many are expected to be heterozygous?

You discover a simple microbe which has a minimal genome. it only has 30 genes ...

By Suman Patra How many gene pairs are involved in a cross involving polygenic inheritance ...

By Sahil Gupta How to calculate number of bonds cleaved by trypsin and chymotrypsin if ...

By Sahil Gupta How to estimate number of amino acid residues in protein if molecular ...

By Sahil Gupta How to calculate molecular mass of tripeptide if molecular mass of amino ...

You must be logged in to post a comment.

Frequency of allele A (p) = 0.7 or 70%

Frequency of allele a (q) = 0.3 or 30%

Total number of individuals(p2 + 2pq + q2) =250

First we have to found out, 2pq (Heterozygous genotype) = 2 x 0.7 x 0.3 = 0.42 or 42%

in 250 populations, 42% individuals are heterozygous i.e.,

250 x (42/100) or 250 x 0.42= 105