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Protein X has 2 trytophans and 1 tyrosine, its M.W is 20,000da. one molar tryptophan and one molar tyrosine solns give A at 280nm of 5500 & 1490 respt. What A at 280nm will u expect for 0.2mg/ml of protein X soln??
Home » Queries & Discussions » Protein X has 2 trytophans and 1 tyrosine, its M.W is 20,000da. one molar tryptophan and one molar tyrosine solns give A at 280nm of 5500 & 1490 respt. What A at 280nm will u expect for 0.2mg/ml of protein X soln??
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To calculate the absorbance of a 1M solution of a protein you simply count up the number of Tryptophan residues and multiply that by the absorbance of a one molar solution of Tryptophan. Then add that to the number of Tyrosine residues multiplied by the absorbance of a one molar solution of Tyrosine, and the sum is the absorbance of 1M of the whole molecule. So we use this simple equation;
Molar Extinction Coefficient = (Number of Tryptophan residues X 5500) + (Number of Tyrosine residues X 1490)
= 2 x 5500 + 1 x 1490
= 12490
absorbance, can be further calculated by simply dividing the Molar Extinction Coefficient by the molecular weight of Protein X which in this case is 20,000
And 0.2mg/mL will have no effect over it?