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What is the number of hydrogen bonds in a b-DNA of 1000 base pairs with the proportion of C,A,T in one of the strands corresponding to 60% 30% and 10% respectively?
Home » Queries & Discussions » What is the number of hydrogen bonds in a b-DNA of 1000 base pairs with the proportion of C,A,T in one of the strands corresponding to 60% 30% and 10% respectively?
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As we can clearly see from the question given above that C is 60%, A is 30% and T is 10%.
Total Number of Base Pairs = 1000.
Now, C = 60% of 1000 = X 1000 = 600.
A = 30% of 1000 = X 1000 = 300.
T = 10% of 1000 = X 1000 = 100.
As per the Watson-Crick structure, three hydrogen bonds can form between G and C, and only two can form between A and T.
Hence, there are 600 Cs that will pair complementary to G on the other strand with three hydrogen bonds. And 300 As that will pair complementary to T on the other strand with two hydrogen bonds and also 100 Ts that will pair complementary to a on the other strand with two hydrogen bonds.
Therefore, we have,
3 X 600 + 2 X 300 + 2 X 100
= 1800 + 600 + 200
= 2600.
We have total of 2600 hydrogen bonds.